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Parse XML using DOM file and run XPath query.
Code:

import org
.w3c.dom.*;
import javax.xml.xpath.*;
import javax.xml.parsers.*;
import java.io.IOException;
import org.xml.sax.SAXException;

public class XpathWork {

    public static void main(String[] args)
            throws ParserConfigurationException, SAXException,
            IOException, XPathExpressionException {

        // Reading xml file using DOM
        DocumentBuilderFactory domFactory =
                DocumentBuilderFactory.newInstance();
        domFactory.setNamespaceAware(true);
        DocumentBuilder builder = domFactory.newDocumentBuilder();
        Document docment = builder.parse("file.xml");
        XPath xpathObject = XPathFactory.newInstance().newXPath();
        // Run the query
        XPathExpression xpathExpression = xpathObject.compile("//*[count(Info)=3]");
        //Select elements which have three children Info
        System.out.println("Getting elements which have three sub nodes of type Info");
        Object result = xpathExpression.evaluate(docment, XPathConstants.NODESET);
        NodeList allNodes = (NodeList) result;
        for (int i = 0; i < allNodes.getLength(); i++) {
            System.out.println(allNodes.item(i).getNodeName());
        }
        System.out.println("Getting elements which have 3 sub nodes");
        xpathExpression = xpathObject.compile("//*[count(*)=3]");
        //Select elements which have any three children Info
        result = xpathExpression.evaluate(docment, XPathConstants.NODESET);
        allNodes = (NodeList) result;
        for (int i = 0; i < allNodes.getLength(); i++) {
            System.out.println("Node name = " + allNodes.item(i).getNodeName());
        }
    }
}
 


XML file:
Code:
<?xml version="1.0" ?>
<Student>
  <Name>
  <Info/>
  <Info/>
  <Info/>
  </Name>
  <Age>
  <Info/>
  <Info/>
  </Age>
  <Address>
<Info/>
<Info/>
  </Address>
</Student>




_________________
M. S. Rakha, Ph.D.
Queen's University
Canada


Author:
Mastermind
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