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Implementing fibonacci sequence problem using iterations
cpp code
`#include <iostream>#include <iomanip>using namespace std;//function declarationdouble fibonacci(unsigned int n);int main(){	int n;		cout << "Enter a number: ";	cin >> n;		//An 'If' condition to prevent the user from entering -ve integers	if (n<0){		cout << "Please Enter a positive integer!" << endl;		return 0;	}	else		cout << "The fibonacci number is " << fibonacci(n) << endl;				cout << "The fibonacci sequence is as follows:" << endl;		//Print Table Heading	cout << setw(10) << "n" << setw(10) << " | " << setw(10) << "F(n)" << endl;    	cout << "-----------------------------------------" << endl;		//A Loop to print fibonacci numbers until 'n' in a tabular form	for(int i=0;i<=n;i++)		cout << setw(10) << i << setw(10) << " | " << setw(10) << fibonacci(i) << endl;	return 0;}//function definitiondouble fibonacci(unsigned int n){	//n_minus_1 represents what's supposed to be F(n-1)	//n_minus_2 represents what's supposed to be F(n-2)	//sum represents F(n) which equals F(n-1)+F(n-2)	double n_minus_1=0,n_minus_2=1,sum;			switch(n)	{	//if n=0 then F(n)=0	case 0:		return 0;		//if n=1 then F(n)=1	case 1:		return 1;			//otherwise the sum (i.e F(n)) is equal to (n_minus_1)+(n_minus_2) (i.e F(n-1)+F(n-2)	//the counter keeps on moving the variables areound 'n' times	//so that on each time F(n-2) becomes equal to F(n-1) and F(n-1) becomes equal to F(n)	//and F(n) is reevaluated each time in the loop	default:		for(int counter=0;counter<n;counter++)		{			sum=n_minus_1+n_minus_2;			n_minus_2=n_minus_1;			n_minus_1=sum ;		}	}	return sum;}`

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M. S. Rakha, Ph.D.
Queen's University

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